Answer:
(a3 – b3) = (a – b)(a2 + b2 + ab)
Let us prove this by consider a = 5 and b= 3 then
(53 – 33) = (5 – 3)(52 + 32 + 5 × 3)
LHS = (125 – 27)
LHS = 98
RHS = (a – b)(a2 + b2 + ab)
RHS = (5 – 3)(52 + 32 + 5 × 3)
RHS = (2) X (25 + 9 + 5 × 3)
RHS = (2) X (34 + 15)
RHS = 2 X 49
RHS = 98
∴ LHS = RHS
(a3 – b3) = (a – b)(a2 + b2 + ab)
Hence Proved
What is the importance of the a cube – b cube formula?